唔識做一條數
e條數點計? (i)
put y=1
g(x)=g(x)g(1)
g(x)=0
suppose g(1) 不等於1
g(x)=0which is contradiction(因為g is a non constant function)
so g(x)不等於0
hence
你put y=x 再用contradiction 試下就計到架啦:)
(ii)未諗到~ (i)看上面
(ii)
h(x)=ln
h(x)=ln<-共x個g(e)
h(x)=ln{^x}
h(x)=ln(2^x)
soln=ln(2^x),
i.e. g(e^x)=2^x
g(e^x)=2^x
g(e^x)=2^(xlne) because of lne=1
g(e^x)=2^
g(x)=2^lnx
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